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9x^2+72x=-135
We move all terms to the left:
9x^2+72x-(-135)=0
We add all the numbers together, and all the variables
9x^2+72x+135=0
a = 9; b = 72; c = +135;
Δ = b2-4ac
Δ = 722-4·9·135
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(72)-18}{2*9}=\frac{-90}{18} =-5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(72)+18}{2*9}=\frac{-54}{18} =-3 $
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